How do you check whether a root-to-leaf path sums to a target?
PICTURE THIS: STACK VS QUEUE
Simple meaning
DFS subtracting the node value, succeeding when you hit a leaf and remaining target is zero.
WHY — Trees instead of guessing?
Why interviewers care about Trees:
question about Trees.
trade-offs, and what you would actually do on a DSA project - not buzzwords.
Name the idea, why it exists, then one short example.
End with when you use it and one common pitfall.
STEPS — What happens step by step?
Before you speak the answer, walk the interviewer through these steps:
- 1DFS subtracting the node
value, succeeding when you hit a leaf and remaining target is zero.
- 2Time is O(n) and
space is O(h).
- 3BFS with remaining sums
on a queue is equivalent and avoids recursion depth issues on skewed trees.
- 4Give an example
One tiny concrete case you can say aloud.
- 5Common mistake
What juniors usually get wrong.
- 6Close
When you pick this over the alternative.
EXAMPLE — See it in action
Here's a short line you can speak, broken into clear beats:
Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.
Key takeaway
DFS subtracting the node value, succeeding when you hit a leaf and remaining target is zero. Time is O(n) and space is O(h).