High Graphs Question 172 of 224

How do you find the length of the shortest word ladder from beginWord to endWord?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: DATA SPLIT

Train 70%Val 15%Test 15%

Fit on train, tune on val, report on test once.

Simple meaning

BFS on the word graph where edges are one-letter differences

1

WHY — Graphs instead of guessing?

Why interviewers care about Graphs:

This is a process

question about Graphs.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    BFS on the word

    graph where edges are one-letter differences

  2. 2
    wildcard buckets like *ot/h*t/ho*

    build adjacency in O(n * L^2) and BFS is O(n * L).

  3. 3
    Bidirectional BFS is a

    common optimization.

  4. 4
    DFS is the wrong

    tool because you need shortest unweighted distance.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“Bidirectional BFS is a common optimization.”
Break into beats
BidirectionalBFSisacommonoptimization
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

BFS on the word graph where edges are one-letter differences wildcard buckets like *ot/h*t/ho* build adjacency in O(n * L^2) and BFS is O(n * L).

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