Easy Hashing Question 19 of 224

How do you find the majority element that appears more than n/2 times?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: HASH MAP

Key"user_id"
Hashslot 17
Valuethe record

Simple meaning

Boyer-Moore voting keeps a candidate and a count, resetting when the count hits zero

1

WHY — Hashing instead of guessing?

Why interviewers care about Hashing:

This is a process

question about Hashing.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    Boyer-Moore voting keeps a

    candidate and a count, resetting when the count hits zero

  2. 2
    Why it exists

    the guaranteed majority wins.

  3. 3
    That is O(n) time

    and O(1) space.

  4. 4
    A hash map of

    frequencies is O(n) space and easier to explain if you have not memorized voting.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“That is O(n) time and O(1) space.”
Break into beats
ThatisOntimeand
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

Boyer-Moore voting keeps a candidate and a count, resetting when the count hits zero the guaranteed majority wins.

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