Easy Two Pointers Question 22 of 224

How do you remove duplicates from a sorted array in place?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: ARRAY IN MEMORY

01234

Index starts at 0. Scan once for max — O(n).

Simple meaning

A slow pointer marks the end of the unique prefix

1

WHY — Two Pointers instead of guessing?

Why interviewers care about Two Pointers:

This is a process

question about Two Pointers.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    A slow pointer marks

    the end of the unique prefix

  2. 2
    a fast pointer copies

    a value only when it differs from the last unique.

  3. 3
    One O(n) pass and

    O(1) extra space, returning the new length.

  4. 4
    This only works because

    equals are adjacent after sorting.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“One O(n) pass and O(1) extra space, returning the new length.”
Break into beats
OneOnpassandO
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

A slow pointer marks the end of the unique prefix a fast pointer copies a value only when it differs from the last unique.

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