How do you solve 0/1 knapsack for weight capacity W?
PICTURE THIS: DJANGO MVT
Simple meaning
dp[w] is the best value using capacity w
WHY — DP instead of guessing?
Why interviewers care about DP:
question about DP.
trade-offs, and what you would actually do on a DSA project - not buzzwords.
Name the idea, why it exists, then one short example.
End with when you use it and one common pitfall.
STEPS — What happens step by step?
Before you speak the answer, walk the interviewer through these steps:
- 1dp[w] is the best
value using capacity w
- 2iterate items and walk
weights backward so each item is used at most once.
- 3Time is O(n*W) and
space is O(W) for the 1D form.
- 4Forward iteration would turn
it into unbounded knapsack, a common bug.
- 5Common mistake
What juniors usually get wrong.
- 6Close
When you pick this over the alternative.
EXAMPLE — See it in action
Here's a short line you can speak, broken into clear beats:
Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.
Key takeaway
dp[w] is the best value using capacity w iterate items and walk weights backward so each item is used at most once.