High Two Pointers Question 150 of 224

How do you find all unique quadruplets that sum to a target?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: HASH MAP

Key"user_id"
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Valuethe record

Simple meaning

Sort, then two nested loops plus an inner two-pointer pair, skipping duplicates at every level.

1

WHY — Two Pointers instead of guessing?

Why interviewers care about Two Pointers:

This is a process

question about Two Pointers.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    Sort, then two nested

    loops plus an inner two-pointer pair, skipping duplicates at every level.

  2. 2
    Time is O(n^3) after

    O(n log n) sort, extra space O(1) besides output.

  3. 3
    Hashing inner two-sums is

    similar time with more memory and messier dedup.

  4. 4
    Give an example

    One tiny concrete case you can say aloud.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“Time is O(n^3) after O(n log n) sort, extra space O(1) besides output.”
Break into beats
TimeisOn3after
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

Sort, then two nested loops plus an inner two-pointer pair, skipping duplicates at every level. Time is O(n^3) after O(n log n) sort, extra space O(1) besides output.

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