Moderate Hashing Question 82 of 224

How do you find the longest consecutive sequence of integers in an unsorted array?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: ARRAY IN MEMORY

01234

Index starts at 0. Scan once for max — O(n).

Simple meaning

Put all numbers in a set, then only start a streak from values that have no predecessor x-1, and walk x+1, x+2, ...

1

WHY — Hashing instead of guessing?

Why interviewers care about Hashing:

This is a process

question about Hashing.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    Put all numbers in

    a set, then only start a streak from values that have no predecessor x-1, and walk x+1, x+2, ...

  2. 2
    Why it exists

    while present.

  3. 3
    Each number is visited

    a constant number of times: O(n) average time and O(n) space.

  4. 4
    Sorting first is O(n

    log n) and is the simpler backup.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“Each number is visited a constant number of times: O(n) average time and O(n) sp”
Break into beats
Eachnumberisvisitedaconstant
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

Put all numbers in a set, then only start a streak from values that have no predecessor x-1, and walk x+1, x+2, ... while present.

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