High Strings Question 145 of 224

How do you find the longest valid parentheses substring?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: STACK VS QUEUE

StackLIFOlast in, first out
QueueFIFOfirst in, first out

Simple meaning

Stack unmatched '(' indices plus a base of the last unmatched ')'

1

WHY — Strings instead of guessing?

Why interviewers care about Strings:

This is a process

question about Strings.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    Stack unmatched '(' indices

    plus a base of the last unmatched ')'

  2. 2
    on a match the

    length is i minus the new top.

  3. 3
    DP is an alternative

    where dp[i] extends a previous valid block

  4. 4
    both are O(n) time

    and O(n) space.

  5. 5
    A two-pass left/right counter

    trick can use O(1) extra space.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“DP is an alternative where dp[i] extends a previous valid block”
Break into beats
DPisanalternativewheredp
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

Stack unmatched '(' indices plus a base of the last unmatched ')' on a match the length is i minus the new top.

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