How do you reverse a string if it is stored as a mutable character array?
PICTURE THIS: ARRAY IN MEMORY
Index starts at 0. Scan once for max — O(n).
Simple meaning
Two pointers swap from both ends until they meet, which is O(n) time and O(1) extra space.
WHY — Strings instead of guessing?
Why interviewers care about Strings:
question about Strings.
trade-offs, and what you would actually do on a DSA project - not buzzwords.
Name the idea, why it exists, then one short example.
End with when you use it and one common pitfall.
STEPS — What happens step by step?
Before you speak the answer, walk the interviewer through these steps:
- 1Two pointers swap from
both ends until they meet, which is O(n) time and O(1) extra space.
- 2In languages where strings
are immutable you allocate a new string, still O(n) time and O(n) space.
- 3Call out immutability so
you do not claim in-place on Python str.
- 4Give an example
One tiny concrete case you can say aloud.
- 5Common mistake
What juniors usually get wrong.
- 6Close
When you pick this over the alternative.
EXAMPLE — See it in action
Here's a short line you can speak, broken into clear beats:
Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.
Key takeaway
Two pointers swap from both ends until they meet, which is O(n) time and O(1) extra space. In languages where strings are immutable you allocate a new string, still O(n) time and O(n) space.