High Recursion Question 196 of 224

How do you solve N-Queens, placing n queens so none attack?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: ARRAY IN MEMORY

01234

Index starts at 0. Scan once for max — O(n).

Simple meaning

Backtrack row by row, skipping used columns and both diagonals (r-c and r+c bit sets or boolean arrays).

1

WHY — Recursion instead of guessing?

Why interviewers care about Recursion:

This is a process

question about Recursion.

Panels listen for order,

trade-offs, and what you would actually do on a DSA project - not buzzwords.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    Backtrack row by row,

    skipping used columns and both diagonals (r-c and r+c bit sets or boolean arrays).

  2. 2
    Worst-case time is exponential,

    roughly O(n!) with pruning, and space is O(n) for the board state.

  3. 3
    Bitmasks of columns and

    diagonals speed the inner check to O(1).

  4. 4
    Give an example

    One tiny concrete case you can say aloud.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“Worst-case time is exponential, roughly O(n!) with pruning, and space is O(n) fo”
Break into beats
Worstcasetimeisexponentialroughly
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

Backtrack row by row, skipping used columns and both diagonals (r-c and r+c bit sets or boolean arrays). Worst-case time is exponential, roughly O(n!) with pruning, and space is O(n) for the board state.

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