Easy Arrays Question 201 of 224

What is the time complexity of accessing an array index?

DSA interview set · Speak this in 60–90 seconds · Faridabad & Delhi NCR

PICTURE THIS: ARRAY IN MEMORY

01234

Index starts at 0. Scan once for max — O(n).

Simple meaning

Access by index is O(1) because the address is base plus index times size.

1

WHY — Arrays instead of guessing?

Why interviewers care about Arrays:

Arrays questions separate people

who only read docs from people who shipped.

Keep it short, concrete,

and tied to DSA work.

Stay structured

Name the idea, why it exists, then one short example.

Close cleanly

End with when you use it and one common pitfall.

2

STEPS — What happens step by step?

Before you speak the answer, walk the interviewer through these steps:

  1. 1
    Access by index is

    O(1) because the address is base plus index times size.

  2. 2
    Searching an unsorted array

    without an index map is O(n).

  3. 3
    I separate access from

    search in interviews.

  4. 4
    Give an example

    One tiny concrete case you can say aloud.

  5. 5
    Common mistake

    What juniors usually get wrong.

  6. 6
    Close

    When you pick this over the alternative.

3

EXAMPLE — See it in action

Here's a short line you can speak, broken into clear beats:

Say this line
“Searching an unsorted array without an index map is O(n).”
Break into beats
Searchinganunsortedarraywithoutan
Speaking order
2987408337471632900

Note: Adapt this scaffold to your own project — keep it under 60–90 seconds.

Key takeaway

Access by index is O(1) because the address is base plus index times size. Searching an unsorted array without an index map is O(n).

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